Operator expressions
Syntax
OperatorExpression :
BorrowExpression
| DereferenceExpression
| ErrorPropagationExpression
| NegationExpression
| ArithmeticOrLogicalExpression
| ComparisonExpression
| LazyBooleanExpression
| TypeCastExpression
| AssignmentExpression
| CompoundAssignmentExpression
Operators are defined for built in types by the Rust language.
Many of the following operators can also be overloaded using traits in std::ops
or std::cmp
.
Overflow
Integer operators will panic when they overflow when compiled in debug mode.
The -C debug-assertions
and -C overflow-checks
compiler flags can be used to control this more directly.
The following things are considered to be overflow:
- When
+
,*
or binary-
create a value greater than the maximum value, or less than the minimum value that can be stored. - Applying unary
-
to the most negative value of any signed integer type, unless the operand is a literal expression (or a literal expression standing alone inside one or more grouped expressions). - Using
/
or%
, where the left-hand argument is the smallest integer of a signed integer type and the right-hand argument is-1
. These checks occur even when-C overflow-checks
is disabled, for legacy reasons. - Using
<<
or>>
where the right-hand argument is greater than or equal to the number of bits in the type of the left-hand argument, or is negative.
Note: The exception for literal expressions behind unary
-
means that forms such as-128_i8
orlet j: i8 = -(128)
never cause a panic and have the expected value of -128.In these cases, the literal expression already has the most negative value for its type (for example,
128_i8
has the value -128) because integer literals are truncated to their type per the description in Integer literal expressions.Negation of these most negative values leaves the value unchanged due to two’s complement overflow conventions.
In
rustc
, these most negative expressions are also ignored by theoverflowing_literals
lint check.
Borrow operators
Syntax
BorrowExpression :
(&
|&&
) Expression
| (&
|&&
)mut
Expression
| (&
|&&
)raw
const
Expression
| (&
|&&
)raw
mut
Expression
The &
(shared borrow) and &mut
(mutable borrow) operators are unary prefix operators.
When applied to a place expression, this expressions produces a reference (pointer) to the location that the value refers to.
The memory location is also placed into a borrowed state for the duration of the reference.
For a shared borrow (&
), this implies that the place may not be mutated, but it may be read or shared again.
For a mutable borrow (&mut
), the place may not be accessed in any way until the borrow expires.
&mut
evaluates its operand in a mutable place expression context.
If the &
or &mut
operators are applied to a value expression, then a temporary value is created.
These operators cannot be overloaded.
#![allow(unused)] fn main() { { // a temporary with value 7 is created that lasts for this scope. let shared_reference = &7; } let mut array = [-2, 3, 9]; { // Mutably borrows `array` for this scope. // `array` may only be used through `mutable_reference`. let mutable_reference = &mut array; } }
Even though &&
is a single token (the lazy ‘and’ operator), when used in the context of borrow expressions it works as two borrows:
#![allow(unused)] fn main() { // same meanings: let a = && 10; let a = & & 10; // same meanings: let a = &&&& mut 10; let a = && && mut 10; let a = & & & & mut 10; }
Raw borrow operators
&raw const
and &raw mut
are the raw borrow operators.
The operand expression of these operators is evaluated in place expression context.
&raw const expr
then creates a const raw pointer of type *const T
to the given place, and &raw mut expr
creates a mutable raw pointer of type *mut T
.
The raw borrow operators must be used instead of a borrow operator whenever the place expression could evaluate to a place that is not properly aligned or does not store a valid value as determined by its type, or whenever creating a reference would introduce incorrect aliasing assumptions. In those situations, using a borrow operator would cause undefined behavior by creating an invalid reference, but a raw pointer may still be constructed.
The following is an example of creating a raw pointer to an unaligned place through a packed
struct:
#![allow(unused)] fn main() { #[repr(packed)] struct Packed { f1: u8, f2: u16, } let packed = Packed { f1: 1, f2: 2 }; // `&packed.f2` would create an unaligned reference, and thus be undefined behavior! let raw_f2 = &raw const packed.f2; assert_eq!(unsafe { raw_f2.read_unaligned() }, 2); }
The following is an example of creating a raw pointer to a place that does not contain a valid value:
#![allow(unused)] fn main() { use std::mem::MaybeUninit; struct Demo { field: bool, } let mut uninit = MaybeUninit::<Demo>::uninit(); // `&uninit.as_mut().field` would create a reference to an uninitialized `bool`, // and thus be undefined behavior! let f1_ptr = unsafe { &raw mut (*uninit.as_mut_ptr()).field }; unsafe { f1_ptr.write(true); } let init = unsafe { uninit.assume_init() }; }
The dereference operator
Syntax
DereferenceExpression :
*
Expression
The *
(dereference) operator is also a unary prefix operator.
When applied to a pointer it denotes the pointed-to location.
If the expression is of type &mut T
or *mut T
, and is either a local variable, a (nested) field of a local variable or is a mutable place expression, then the resulting memory location can be assigned to.
Dereferencing a raw pointer requires unsafe
.
On non-pointer types *x
is equivalent to *std::ops::Deref::deref(&x)
in an immutable place expression context and *std::ops::DerefMut::deref_mut(&mut x)
in a mutable place expression context.
#![allow(unused)] fn main() { let x = &7; assert_eq!(*x, 7); let y = &mut 9; *y = 11; assert_eq!(*y, 11); }
The question mark operator
Syntax
ErrorPropagationExpression :
Expression?
The question mark operator (?
) unwraps valid values or returns erroneous values, propagating them to the calling function.
It is a unary postfix operator that can only be applied to the types Result<T, E>
and Option<T>
.
When applied to values of the Result<T, E>
type, it propagates errors.
If the value is Err(e)
, then it will return Err(From::from(e))
from the enclosing function or closure.
If applied to Ok(x)
, then it will unwrap the value to evaluate to x
.
#![allow(unused)] fn main() { use std::num::ParseIntError; fn try_to_parse() -> Result<i32, ParseIntError> { let x: i32 = "123".parse()?; // x = 123 let y: i32 = "24a".parse()?; // returns an Err() immediately Ok(x + y) // Doesn't run. } let res = try_to_parse(); println!("{:?}", res); assert!(res.is_err()) }
When applied to values of the Option<T>
type, it propagates None
s.
If the value is None
, then it will return None
.
If applied to Some(x)
, then it will unwrap the value to evaluate to x
.
#![allow(unused)] fn main() { fn try_option_some() -> Option<u8> { let val = Some(1)?; Some(val) } assert_eq!(try_option_some(), Some(1)); fn try_option_none() -> Option<u8> { let val = None?; Some(val) } assert_eq!(try_option_none(), None); }
?
cannot be overloaded.
Negation operators
Syntax
NegationExpression :
-
Expression
|!
Expression
These are the last two unary operators. This table summarizes the behavior of them on primitive types and which traits are used to overload these operators for other types. Remember that signed integers are always represented using two’s complement. The operands of all of these operators are evaluated in value expression context so are moved or copied.
Symbol | Integer | bool | Floating Point | Overloading Trait |
---|---|---|---|---|
- | Negation* | Negation | std::ops::Neg | |
! | Bitwise NOT | Logical NOT | std::ops::Not |
* Only for signed integer types.
Here are some example of these operators
#![allow(unused)] fn main() { let x = 6; assert_eq!(-x, -6); assert_eq!(!x, -7); assert_eq!(true, !false); }
Arithmetic and Logical Binary Operators
Syntax
ArithmeticOrLogicalExpression :
Expression+
Expression
| Expression-
Expression
| Expression*
Expression
| Expression/
Expression
| Expression%
Expression
| Expression&
Expression
| Expression|
Expression
| Expression^
Expression
| Expression<<
Expression
| Expression>>
Expression
Binary operators expressions are all written with infix notation. This table summarizes the behavior of arithmetic and logical binary operators on primitive types and which traits are used to overload these operators for other types. Remember that signed integers are always represented using two’s complement. The operands of all of these operators are evaluated in value expression context so are moved or copied.
Symbol | Integer | bool | Floating Point | Overloading Trait | Overloading Compound Assignment Trait |
---|---|---|---|---|---|
+ | Addition | Addition | std::ops::Add | std::ops::AddAssign | |
- | Subtraction | Subtraction | std::ops::Sub | std::ops::SubAssign | |
* | Multiplication | Multiplication | std::ops::Mul | std::ops::MulAssign | |
/ | Division*† | Division | std::ops::Div | std::ops::DivAssign | |
% | Remainder**† | Remainder | std::ops::Rem | std::ops::RemAssign | |
& | Bitwise AND | Logical AND | std::ops::BitAnd | std::ops::BitAndAssign | |
| | Bitwise OR | Logical OR | std::ops::BitOr | std::ops::BitOrAssign | |
^ | Bitwise XOR | Logical XOR | std::ops::BitXor | std::ops::BitXorAssign | |
<< | Left Shift | std::ops::Shl | std::ops::ShlAssign | ||
>> | Right Shift*** | std::ops::Shr | std::ops::ShrAssign |
* Integer division rounds towards zero.
** Rust uses a remainder defined with truncating division. Given remainder = dividend % divisor
, the remainder will have the same sign as the dividend.
*** Arithmetic right shift on signed integer types, logical right shift on unsigned integer types.
† For integer types, division by zero panics.
Here are examples of these operators being used.
#![allow(unused)] fn main() { assert_eq!(3 + 6, 9); assert_eq!(5.5 - 1.25, 4.25); assert_eq!(-5 * 14, -70); assert_eq!(14 / 3, 4); assert_eq!(100 % 7, 2); assert_eq!(0b1010 & 0b1100, 0b1000); assert_eq!(0b1010 | 0b1100, 0b1110); assert_eq!(0b1010 ^ 0b1100, 0b110); assert_eq!(13 << 3, 104); assert_eq!(-10 >> 2, -3); }
Comparison Operators
Syntax
ComparisonExpression :
Expression==
Expression
| Expression!=
Expression
| Expression>
Expression
| Expression<
Expression
| Expression>=
Expression
| Expression<=
Expression
Comparison operators are also defined both for primitive types and many types in the standard library.
Parentheses are required when chaining comparison operators. For example, the expression a == b == c
is invalid and may be written as (a == b) == c
.
Unlike arithmetic and logical operators, the traits for overloading these operators are used more generally to show how a type may be compared and will likely be assumed to define actual comparisons by functions that use these traits as bounds. Many functions and macros in the standard library can then use that assumption (although not to ensure safety). Unlike the arithmetic and logical operators above, these operators implicitly take shared borrows of their operands, evaluating them in place expression context:
#![allow(unused)] fn main() { let a = 1; let b = 1; a == b; // is equivalent to ::std::cmp::PartialEq::eq(&a, &b); }
This means that the operands don’t have to be moved out of.
Symbol | Meaning | Overloading method |
---|---|---|
== | Equal | std::cmp::PartialEq::eq |
!= | Not equal | std::cmp::PartialEq::ne |
> | Greater than | std::cmp::PartialOrd::gt |
< | Less than | std::cmp::PartialOrd::lt |
>= | Greater than or equal to | std::cmp::PartialOrd::ge |
<= | Less than or equal to | std::cmp::PartialOrd::le |
Here are examples of the comparison operators being used.
#![allow(unused)] fn main() { assert!(123 == 123); assert!(23 != -12); assert!(12.5 > 12.2); assert!([1, 2, 3] < [1, 3, 4]); assert!('A' <= 'B'); assert!("World" >= "Hello"); }
Lazy boolean operators
Syntax
LazyBooleanExpression :
Expression||
Expression
| Expression&&
Expression
The operators ||
and &&
may be applied to operands of boolean type.
The ||
operator denotes logical ‘or’, and the &&
operator denotes logical ‘and’.
They differ from |
and &
in that the right-hand operand is only evaluated when the left-hand operand does not already determine the result of the expression.
That is, ||
only evaluates its right-hand operand when the left-hand operand evaluates to false
, and &&
only when it evaluates to true
.
#![allow(unused)] fn main() { let x = false || true; // true let y = false && panic!(); // false, doesn't evaluate `panic!()` }
Type cast expressions
Syntax
TypeCastExpression :
Expressionas
TypeNoBounds
A type cast expression is denoted with the binary operator as
.
Executing an as
expression casts the value on the left-hand side to the type on the right-hand side.
An example of an as
expression:
#![allow(unused)] fn main() { fn sum(values: &[f64]) -> f64 { 0.0 } fn len(values: &[f64]) -> i32 { 0 } fn average(values: &[f64]) -> f64 { let sum: f64 = sum(values); let size: f64 = len(values) as f64; sum / size } }
as
can be used to explicitly perform coercions, as well as the following additional casts.
Any cast that does not fit either a coercion rule or an entry in the table is a compiler error.
Here *T
means either *const T
or *mut T
. m
stands for optional mut
in
reference types and mut
or const
in pointer types.
Type of e | U | Cast performed by e as U |
---|---|---|
Integer or Float type | Integer or Float type | Numeric cast |
Enumeration | Integer type | Enum cast |
bool or char | Integer type | Primitive to integer cast |
u8 | char | u8 to char cast |
*T | *V where V: Sized * | Pointer to pointer cast |
*T where T: Sized | Integer type | Pointer to address cast |
Integer type | *V where V: Sized | Address to pointer cast |
&m₁ T | *m₂ T ** | Reference to pointer cast |
&m₁ [T; n] | *m₂ T ** | Array to pointer cast |
Function item | Function pointer | Function item to function pointer cast |
Function item | *V where V: Sized | Function item to pointer cast |
Function item | Integer | Function item to address cast |
Function pointer | *V where V: Sized | Function pointer to pointer cast |
Function pointer | Integer | Function pointer to address cast |
Closure *** | Function pointer | Closure to function pointer cast |
* or T
and V
are compatible unsized types, e.g., both slices, both the same trait object.
** only when m₁
is mut
or m₂
is const
. Casting mut
reference to
const
pointer is allowed.
*** only for closures that do not capture (close over) any local variables
Semantics
Numeric cast
- Casting between two integers of the same size (e.g. i32 -> u32) is a no-op (Rust uses 2’s complement for negative values of fixed integers)
- Casting from a larger integer to a smaller integer (e.g. u32 -> u8) will truncate
- Casting from a smaller integer to a larger integer (e.g. u8 -> u32) will
- zero-extend if the source is unsigned
- sign-extend if the source is signed
- Casting from a float to an integer will round the float towards zero
NaN
will return0
- Values larger than the maximum integer value, including
INFINITY
, will saturate to the maximum value of the integer type. - Values smaller than the minimum integer value, including
NEG_INFINITY
, will saturate to the minimum value of the integer type.
- Casting from an integer to float will produce the closest possible float *
- if necessary, rounding is according to
roundTiesToEven
mode *** - on overflow, infinity (of the same sign as the input) is produced
- note: with the current set of numeric types, overflow can only happen
on
u128 as f32
for values greater or equal tof32::MAX + (0.5 ULP)
- if necessary, rounding is according to
- Casting from an f32 to an f64 is perfect and lossless
- Casting from an f64 to an f32 will produce the closest possible f32 **
- if necessary, rounding is according to
roundTiesToEven
mode *** - on overflow, infinity (of the same sign as the input) is produced
- if necessary, rounding is according to
* if integer-to-float casts with this rounding mode and overflow behavior are not supported natively by the hardware, these casts will likely be slower than expected.
** if f64-to-f32 casts with this rounding mode and overflow behavior are not supported natively by the hardware, these casts will likely be slower than expected.
*** as defined in IEEE 754-2008 §4.3.1: pick the nearest floating point number, preferring the one with an even least significant digit if exactly halfway between two floating point numbers.
Enum cast
Casts an enum to its discriminant, then uses a numeric cast if needed. Casting is limited to the following kinds of enumerations:
- Unit-only enums
- Field-less enums without explicit discriminants, or where only unit-variants have explicit discriminants
Primitive to integer cast
false
casts to0
,true
casts to1
char
casts to the value of the code point, then uses a numeric cast if needed.
u8
to char
cast
Casts to the char
with the corresponding code point.
Pointer to address cast
Casting from a raw pointer to an integer produces the machine address of the referenced memory.
If the integer type is smaller than the pointer type, the address may be truncated; using usize
avoids this.
Address to pointer cast
Casting from an integer to a raw pointer interprets the integer as a memory address and produces a pointer referencing that memory.
Warning: This interacts with the Rust memory model, which is still under development. A pointer obtained from this cast may suffer additional restrictions even if it is bitwise equal to a valid pointer. Dereferencing such a pointer may be undefined behavior if aliasing rules are not followed.
A trivial example of sound address arithmetic:
#![allow(unused)] fn main() { let mut values: [i32; 2] = [1, 2]; let p1: *mut i32 = values.as_mut_ptr(); let first_address = p1 as usize; let second_address = first_address + 4; // 4 == size_of::<i32>() let p2 = second_address as *mut i32; unsafe { *p2 += 1; } assert_eq!(values[1], 3); }
Pointer-to-pointer cast
*const T
/ *mut T
can be cast to *const U
/ *mut U
with the following behavior:
-
If
T
andU
are both sized, the pointer is returned unchanged. -
If
T
andU
are both unsized, the pointer is also returned unchanged. In particular, the metadata is preserved exactly.For instance, a cast from
*const [T]
to*const [U]
preserves the number of elements. Note that, as a consequence, such casts do not necessarily preserve the size of the pointer’s referent (e.g., casting*const [u16]
to*const [u8]
will result in a raw pointer which refers to an object of half the size of the original). The same holds forstr
and any compound type whose unsized tail is a slice type, such asstruct Foo(i32, [u8])
or(u64, Foo)
. -
If
T
is unsized andU
is sized, the cast discards all metadata that completes the wide pointerT
and produces a thin pointerU
consisting of the data part of the unsized pointer.
Assignment expressions
Syntax
AssignmentExpression :
Expression=
Expression
An assignment expression moves a value into a specified place.
An assignment expression consists of a mutable assignee expression, the assignee operand, followed by an equals sign (=
) and a value expression, the assigned value operand.
In its most basic form, an assignee expression is a place expression, and we discuss this case first.
The more general case of destructuring assignment is discussed below, but this case always decomposes into sequential assignments to place expressions, which may be considered the more fundamental case.
Basic assignments
Evaluating assignment expressions begins by evaluating its operands. The assigned value operand is evaluated first, followed by the assignee expression. For destructuring assignment, subexpressions of the assignee expression are evaluated left-to-right.
Note: This is different than other expressions in that the right operand is evaluated before the left one.
It then has the effect of first dropping the value at the assigned place, unless the place is an uninitialized local variable or an uninitialized field of a local variable. Next it either copies or moves the assigned value to the assigned place.
An assignment expression always produces the unit value.
Example:
#![allow(unused)] fn main() { let mut x = 0; let y = 0; x = y; }
Destructuring assignments
Destructuring assignment is a counterpart to destructuring pattern matches for variable declaration, permitting assignment to complex values, such as tuples or structs. For instance, we may swap two mutable variables:
#![allow(unused)] fn main() { let (mut a, mut b) = (0, 1); // Swap `a` and `b` using destructuring assignment. (b, a) = (a, b); }
In contrast to destructuring declarations using let
, patterns may not appear on the left-hand side of an assignment due to syntactic ambiguities.
Instead, a group of expressions that correspond to patterns are designated to be assignee expressions, and permitted on the left-hand side of an assignment.
Assignee expressions are then desugared to pattern matches followed by sequential assignment.
The desugared patterns must be irrefutable: in particular, this means that only slice patterns whose length is known at compile-time, and the trivial slice [..]
, are permitted for destructuring assignment.
The desugaring method is straightforward, and is illustrated best by example.
#![allow(unused)] fn main() { struct Struct { x: u32, y: u32 } let (mut a, mut b) = (0, 0); (a, b) = (3, 4); [a, b] = [3, 4]; Struct { x: a, y: b } = Struct { x: 3, y: 4}; // desugars to: { let (_a, _b) = (3, 4); a = _a; b = _b; } { let [_a, _b] = [3, 4]; a = _a; b = _b; } { let Struct { x: _a, y: _b } = Struct { x: 3, y: 4}; a = _a; b = _b; } }
Identifiers are not forbidden from being used multiple times in a single assignee expression.
Underscore expressions and empty range expressions may be used to ignore certain values, without binding them.
Note that default binding modes do not apply for the desugared expression.
Compound assignment expressions
Syntax
CompoundAssignmentExpression :
Expression+=
Expression
| Expression-=
Expression
| Expression*=
Expression
| Expression/=
Expression
| Expression%=
Expression
| Expression&=
Expression
| Expression|=
Expression
| Expression^=
Expression
| Expression<<=
Expression
| Expression>>=
Expression
Compound assignment expressions combine arithmetic and logical binary operators with assignment expressions.
For example:
#![allow(unused)] fn main() { let mut x = 5; x += 1; assert!(x == 6); }
The syntax of compound assignment is a mutable place expression, the assigned operand, then one of the operators followed by an =
as a single token (no whitespace), and then a value expression, the modifying operand.
Unlike other place operands, the assigned place operand must be a place expression. Attempting to use a value expression is a compiler error rather than promoting it to a temporary.
Evaluation of compound assignment expressions depends on the types of the operators.
If both types are primitives, then the modifying operand will be evaluated first followed by the assigned operand. It will then set the value of the assigned operand’s place to the value of performing the operation of the operator with the values of the assigned operand and modifying operand.
Note: This is different than other expressions in that the right operand is evaluated before the left one.
Otherwise, this expression is syntactic sugar for calling the function of the overloading compound assignment trait of the operator (see the table earlier in this chapter). A mutable borrow of the assigned operand is automatically taken.
For example, the following expression statements in example
are equivalent:
#![allow(unused)] fn main() { struct Addable; use std::ops::AddAssign; impl AddAssign<Addable> for Addable { /* */ fn add_assign(&mut self, other: Addable) {} } fn example() { let (mut a1, a2) = (Addable, Addable); a1 += a2; let (mut a1, a2) = (Addable, Addable); AddAssign::add_assign(&mut a1, a2); } }
Like assignment expressions, compound assignment expressions always produce the unit value.
Warning: The evaluation order of operands swaps depending on the types of the operands: with primitive types the right-hand side will get evaluated first, while with non-primitive types the left-hand side will get evaluated first. Try not to write code that depends on the evaluation order of operands in compound assignment expressions. See this test for an example of using this dependency.